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**PHYSICS THEORY**

**1a)**

impulse(I)=F*t

F=ma= m(v/t)= M((d/t)/(t))

f=M(l/T)/T)= MLT^-2

I=MLT^-2 * T

I=MLT^-1

1b)

Acceleration(a)=v/t=(d/t)/t

a=d/t^2= L/T^2= LT^-2

1c)

WOrk(w)=f*d

W=MLT^-2 * L

W=ML^2T^-2impulse(I)=F*t

F=ma= m(v/t)= M((d/t)/(t))

f=M(l/T)/T)= MLT^-2

I=MLT^-2 * T

I=MLT^-1

1b)

Acceleration(a)=v/t=(d/t)/t

a=d/t^2= L/T^2= LT^-2

1c)

WOrk(w)=f*d

W=MLT^-2 * L

W=ML^2T^-2

**2)**

Velocity(u)=20ms^-1

Angle(tita)=40 degree

At maximum height, h

V^2=u^2 + 2gh

U^2 sin^2 tita+u

u= 20^2* (sin 40 degree)^2

u=20^2*(sin 4o degree)

u=400* 0.3455

u=138.2ms^-1

Velocity(u)=20ms^-1

Angle(tita)=40 degree

At maximum height, h

V^2=u^2 + 2gh

U^2 sin^2 tita+u

u= 20^2* (sin 40 degree)^2

u=20^2*(sin 4o degree)

u=400* 0.3455

u=138.2ms^-1

**3)**

-smoke

-aerosol

-dust particle

-smoke

-aerosol

-dust particle

**4) Given flux density(B)=0.217**

Force(F)=9.6*10^-12N

Speed(v)=?

F=Bqv

9.6*10^-12= 0.12* 1.6* V

V=(9.6*10^-12)/0.192*10^-19

=50*10^-12+9

v=50*10^7

=5*10^8ms^-1

Force(F)=9.6*10^-12N

Speed(v)=?

F=Bqv

9.6*10^-12= 0.12* 1.6* V

V=(9.6*10^-12)/0.192*10^-19

=50*10^-12+9

v=50*10^7

=5*10^8ms^-1

**5)**

i) For launching astronauts into the space

ii) For launching satellite

iii) For Scientific researchi) For launching astronauts into the space

ii) For launching satellite

iii) For Scientific research

**6a)**

Doping is the addition of small quantity of an element to a semi conductor to change its characteristics

6b)

Doping introduce impurities into an extremely pure instrintic semi conductor for the purpose of modulating its elctrical properties

================================

7)

X = Electron gun

Y = Accelerating mode

Z = Deflection plateDoping is the addition of small quantity of an element to a semi conductor to change its characteristics

6b)

Doping introduce impurities into an extremely pure instrintic semi conductor for the purpose of modulating its elctrical properties

================================

7)

X = Electron gun

Y = Accelerating mode

Z = Deflection plate

**9a)**

i) thermal equilibrium is the point at which the temperature of an object remain constant or steady

ii)fundamental interval is the distance between upper and lower fixed point of a thermometrei) thermal equilibrium is the point at which the temperature of an object remain constant or steady

ii)fundamental interval is the distance between upper and lower fixed point of a thermometre

9b)

i) it can be used to raise heavy load

ii) it is used in printing press

9c)

magnet

9di)

by using calometry law

heat last = heat gain

MmCmDθm=CaDθ + Mw Cw Dθ

300 * Cm * ( 85 - 40 ) = 90 + 500 * 4200

13500Cm = 90 + 29400000

13500CM = 29400090/13500

Cm=2177.78Jg^-K^-1

9dii) §

i) by convection

ii) by conduction

9diii) §

i) power generation

ii) chemical processing

================================**8a)**

Net force: The net force is the vector sum of all the forces that act upon an object. It is also the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out.

8b)

The law of conservation of linear momentum states that the total

momentum of a system of particles remains constant, so long as no

external forces act on the system.

e.g Firing a bullet from a gun or a radioactive nucleus spontaneously emitting an alpha particle.

8c)

M = 200g = 0.2kg, h= 2cm, h2= 1.8m, u = 0, v=?

P.E = mgh

P.E = K.E = 1/2MV^2

4 = 1/2 x 0.2 x V^2

V = √40 = 6.32m/s^-1

Impulse = M(V-U)

Impulse = 0.2 ( 6.32 - (-o))

= 1.264Kgms^-1

8d)

M= 0.02kg , f= 5Hz, x= 10cm = 0.1 , V = 200cm = 2m/s

8dii)

r = ? , w = 2πf = 2x3.142x5

W= 31.4

From V= w √r^2 - 0.1^2

2 = 31.4 √ r^2 - 0.1^2

= r^2 - 0.1^2 = 0.6369^2

r^2 = 0.41564161

r = √ 0.41564161

r = 0.64m

Maximum vel

V = wr (x = 0 at maximum)

8diii)

maximum potential energy

=1/2 MVm^2

=1/2*20^10 *(372.3)^2

=10*138596.4

=1385964JNet force: The net force is the vector sum of all the forces that act upon an object. It is also the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out.

8b)

The law of conservation of linear momentum states that the total

momentum of a system of particles remains constant, so long as no

external forces act on the system.

e.g Firing a bullet from a gun or a radioactive nucleus spontaneously emitting an alpha particle.

8c)

M = 200g = 0.2kg, h= 2cm, h2= 1.8m, u = 0, v=?

P.E = mgh

P.E = K.E = 1/2MV^2

4 = 1/2 x 0.2 x V^2

V = √40 = 6.32m/s^-1

Impulse = M(V-U)

Impulse = 0.2 ( 6.32 - (-o))

= 1.264Kgms^-1

8d)

M= 0.02kg , f= 5Hz, x= 10cm = 0.1 , V = 200cm = 2m/s

8dii)

r = ? , w = 2πf = 2x3.142x5

W= 31.4

From V= w √r^2 - 0.1^2

2 = 31.4 √ r^2 - 0.1^2

= r^2 - 0.1^2 = 0.6369^2

r^2 = 0.41564161

r = √ 0.41564161

r = 0.64m

Maximum vel

V = wr (x = 0 at maximum)

8diii)

maximum potential energy

=1/2 MVm^2

=1/2*20^10 *(372.3)^2

=10*138596.4

=1385964J

9b)

i) it can be used to raise heavy load

ii) it is used in printing press

9c)

magnet

9di)

by using calometry law

heat last = heat gain

MmCmDθm=CaDθ + Mw Cw Dθ

300 * Cm * ( 85 - 40 ) = 90 + 500 * 4200

13500Cm = 90 + 29400000

13500CM = 29400090/13500

Cm=2177.78Jg^-K^-1

9dii) §

i) by convection

ii) by conduction

9diii) §

i) power generation

ii) chemical processing

================================

**10a)**

Critical angle is the angle of incidence in the optically densed medium when the angle of refraction is 90degrees

10b)

Anti-note are created by region of maximum displacement in a waveCritical angle is the angle of incidence in the optically densed medium when the angle of refraction is 90degrees

10b)

Anti-note are created by region of maximum displacement in a wave

**11a)**

Dielectric strength is the property of an insulating material to retain material to retain electrical properties

11bi)

-Infra-red wave

-Geiger muller counter

-Scintillation counter

11bii)

Irradiation of solar energy

11c)

Charge(q)=1.0*10^-19C

Electric field intensity(E)=1200NC^-1

Weight of the oil drop=?

E=F/q

1200=F/1.0*10^-19

F=1200*1.0*10^-19

F=1.2*10^3*10^-19

F=1.2*10^-16N

11d)

R=100ohm, L=0.05H, C=0.25uF

V=220v, f=50Hz

11di)

Impedance(z)=sqroot(R^2+(Xl-Xc)^2)

Xl=2*pie*fl

Xl=2*(22/7)*50*0.05

Xl=15.71ohm

Xl=(1/2*pie*fc)

Xc=1/78.55*10^-6

Xc=10^6/78.55

=12730.7ohm

Z=sqroot(100^2+(15.71^2-12730.7^2)

Z=sqroot(10000+2.63*10^16

Z=sqroot(2.63*10^16)

Z=1.62*10^16ohm

11dii)

Vrms=IZ

I=220/1.62*10^16

=1.36*10^-14

================================Dielectric strength is the property of an insulating material to retain material to retain electrical properties

11bi)

-Infra-red wave

-Geiger muller counter

-Scintillation counter

11bii)

Irradiation of solar energy

11c)

Charge(q)=1.0*10^-19C

Electric field intensity(E)=1200NC^-1

Weight of the oil drop=?

E=F/q

1200=F/1.0*10^-19

F=1200*1.0*10^-19

F=1.2*10^3*10^-19

F=1.2*10^-16N

11d)

R=100ohm, L=0.05H, C=0.25uF

V=220v, f=50Hz

11di)

Impedance(z)=sqroot(R^2+(Xl-Xc)^2)

Xl=2*pie*fl

Xl=2*(22/7)*50*0.05

Xl=15.71ohm

Xl=(1/2*pie*fc)

Xc=1/78.55*10^-6

Xc=10^6/78.55

=12730.7ohm

Z=sqroot(100^2+(15.71^2-12730.7^2)

Z=sqroot(10000+2.63*10^16

Z=sqroot(2.63*10^16)

Z=1.62*10^16ohm

11dii)

Vrms=IZ

I=220/1.62*10^16

=1.36*10^-14

================================

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