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Chockes: 2016/2017 NECO Physics Objectives & Theory Answers Posted Here

CURRENT EXAMINATION:

NECO May/June Physics Objectives & Theory Questions & Answers;
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QUESTIONS IN IMAGE FORMAT

PHYSICS OBJECTIVES ANSWERS
1-10: BAEDEECDEB
11-20: CDADDDBCBB
21-30: DBEBBEADEB
31-40: ABEBCBCCDA
41-50: BDBCEDAAAE
51-60: AAABBACECA


PHYSICS THEORY ANSWERS

(1ai)
(i)Rockets are used for space travels.
(ii)Rockets are used for launching satellites into space

(1aii)
(i) Artificial Satellites are used to send signals for televisions,radio, etc
(ii) Artificial satellites they are used for monitoring cloud patterns for a weather station

(1b)
A propeller like piece called turbine is been rotated continuously by falling water from a dam, which then turns a metal shaft in an electric generator,which is the motor that produces electricity

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(2a)
Diagram

(i)distance covered=5m+10m=15m
(ii)magnitude of his displacement
=a^2=b^2+c^2
x^2=5^2+10^2=25+100
x^2=125
x=sqr125
=5sqr5m

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(4a)
(i) Pulley
(ii) The inclined plane

(4b)
Draw the diagram of a plier

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(5)
V1=700cm^3, T1=30dgree-census+273=303k, P1=606mmHg
V2=700-300=400cm^3, T2=47+273=320k
from general gas law
P1V1/T1 = P2V2/T2
606*700/303=P2*400/320
P2=606*700*320/303*400
P2=1120mmHg

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(8a)
Eletric current through a conductor is the rate of flow of charges(eletron)
(8b)
V=Q/ 4 pie E0 R = (1.5*10^-5)/(9*10^9 *0.3)
=(1.5* 10^-5 )/(2.7 * 10^9) = 1.5/2.7 * 10^-5-9
=0.56*10^-14
V=5.6* 10^-4 V

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(9a)
(i)heating method
(ii)eletrical method

(9b)
E=1/2CV^2
E=1/2 * 4*10^-6 * 800^2
E=2*10^-6 * 800^2
E=I.28j



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(11)
Tabulate :

Hard xrays:
(i)high penetration
(ii)produced by hiogh voltage
(iii)short wavelenght

Soft xrays:
(i)low penetration
(ii)produced by low voltage
(iii)long wavelenght

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(12ai)
Centre of gravity can be define as the point through which the line of action of the weight of the body always passes irrespective of the position of the body.

(12aii)
Diagram

(12b)
C.g = centre of gravity
:- v= u - gt
Of maximum height v=O - K
O= u-gt
For vertical component, U =uSin tita
Therefore O= usin tita- gt
gt =uSin tita
T=uSin tita/g
Where T is the time taken to maximum height

(12c)
Taken moment about point A
Cwm = {60*10)+ (20*60)
Cwm=600+1200
Cwm=1800
Acwm = (20*40) + (R3 * 40)
Acwm=800+80R3
At equilibrium, Cwm=Acwm
1800=800+40r3
1800-800=40r3
1000=40r3
R3=1000/40
R3=25N

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(13a)
Dew point is the temperature at which the water vapour present in the atmosphere is just sufficent to saturate it

(13b)
Mist is formed as a result of condensed drops of moisture throughout the mass of cooled air. That is when water droplet in the air cool suddenly

(13ci)
The plastic comb will acquire electric charges

(13cii)
The plasic comb can attract small pieces of paper due to the acquired charges.

(13di)
Area expansivity(B)=2§
=2*1.2*10^-5
B=2.4*10^-5/k

(13dii)
Given that initial length=6cm
initial area A=6*6=36cm^2
rise in temperature =25k
linear expansivity=1.2*10^-5/k
area expansivity =2.4*10^-5/k
new area At=Ao(1+Btita)
At=36(1+2.4*10^-5*25)
At=36(1+ 60*10^-5)
At=36(1+0.0006)
At=36(1.0006)
At=36.0216

====================================


(15a)
electrical potential is the workdone in driving a unit charge of electric current from one point to another in a closed circuit. It is measured in volta(V)

(15b)
DIAGRAM

A metal rod can be made into a magnet by divided touch me thod as shown in the diagram above.
The metal rod is stroke at the middle with opposite pole end of two permanent magnets towards wapbase.org the opposite ends several times opposite polarity are then formed

(15ci)
DIAGRAM

VR=120v---->Vl=50v---->Vc=134.39v
220v,506z

(15cii)
V^2=Vr^2+(Vl-Vc)^2
220^2=120^2+(50-Vc)^2
48400=14400+(50-Vc)^2
48400=14400=(50-Vc)^2
34000=(50-Vc)^2
50-Vc=sqr34000
50-Vc=184.39
-Vc=184.39-50
Vc=134.39v
;the potential difference across the capaitor is 134.39v
centre of gravity can be define as the point through which the line of action of the weight of the body always passes irrespective of the position of the body.



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